Theoretical pH of HOAc + NaOAc Solution

In summary, the problem involves calculating the theoretical pH of a solution consisting of 30.00 mmol of HOAc and 53.00 mmol of NaOAc with no water present. The equation to use requires the concentration or number of moles of the conjugate base in the numerator and the concentration or number of moles of the conjugate acid in the denominator. Simply plugging in the given values will result in a negative number, so further understanding of the chemistry behind the calculation is needed.
  • #1
ahhppull
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Homework Statement


Calculate the theoretical pH of each solution. The first solution was 30.00 mmol of HOAc (acetic acid) and 53.00 mmol of NaOAc. There was no water in this solution.

Homework Equations



We have to use this equation.
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The Attempt at a Solution



I'm unsure of what to plug in. I know HOAc is the weak acid and NaOAC is the strong base? But if I only plug those two numbers I'd have a negative number and you can't take the log of a negative number.
 
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  • #2
NaOAc is not the strong base, it is a conjugate base of AcOH (or HOAc as you wrote it).

Equation you have to use... sigh. Another way of isolating students from understanding the chemistry behind the calculation. You need to have concentration (or number of moles) of conjugate base in the nominator and concentration (or number of moles) of the conjugate acid in the denominator. What you have there now is just a way of calculating numbers of moles from the stoichiometry of the neutralization/protonation reactions.
 

Related to Theoretical pH of HOAc + NaOAc Solution

1. What is the theoretical pH of a HOAc + NaOAc solution?

The theoretical pH of a HOAc + NaOAc solution can be calculated using the Henderson-Hasselbalch equation, which takes into account the concentration of the acid (HOAc) and its conjugate base (NaOAc). The formula is pH = pKa + log([NaOAc]/[HOAc]), where pKa is the acid dissociation constant of HOAc. The pKa value for HOAc is 4.76, so the theoretical pH of a 1:1 ratio of HOAc to NaOAc would be 4.76 + log(1/1) = 4.76. This means that the solution would be slightly acidic.

2. How does the concentration of HOAc affect the theoretical pH of the solution?

The concentration of HOAc directly affects the theoretical pH of the solution. According to the Henderson-Hasselbalch equation, as the concentration of HOAc increases, the pH decreases. This is because a higher concentration of HOAc means there is more acid present, making the solution more acidic. Similarly, decreasing the concentration of HOAc will result in a higher pH.

3. Can the theoretical pH of a HOAc + NaOAc solution be lower than 4.76?

Yes, the theoretical pH of a HOAc + NaOAc solution can be lower than 4.76. This would occur if the concentration of HOAc is higher than the concentration of NaOAc. In this case, the pH would be lower than the pKa of HOAc, resulting in a more acidic solution.

4. How does the addition of a strong acid or base affect the theoretical pH of the solution?

The addition of a strong acid or base will affect the theoretical pH of the solution by changing the concentration of HOAc and NaOAc. For example, adding a strong acid would increase the concentration of HOAc, resulting in a lower pH, while adding a strong base would increase the concentration of NaOAc, resulting in a higher pH.

5. Is the theoretical pH of a HOAc + NaOAc solution the same as the actual pH?

No, the theoretical pH of a HOAc + NaOAc solution is not always the same as the actual pH. The theoretical pH is based on ideal conditions and assumes complete dissociation of the acid and its conjugate base. In reality, other factors such as the presence of impurities or competing reactions may affect the actual pH of the solution.

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