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Buoyancy and Archimedes' Principle (helium ballon carrying cargo), HELP!

  1. Nov 12, 2005 #1
    I can not figure this out for the life of me! I know the answer is 920 kg, but I have to know how to get there so I can do my WebAssign problem!

    Here's the problem:

    " A spherical balloon has a radius of 7.35 m and is filled with helium. How large a cargo can it lift, assuming that the skin and structure of the balloon have a mass of 930 kg? Neglect the buoyant force on the cargo volume itself."

    So the buoyant force must = the weight of the helium plus the weight of the balloon

    So F(b) = (mass of helium + mass of cargo) X 9.8

    F(b) = Density of air X volume X 9.8

    9.8 cancels out on both sides.

    Density of air is 1.29 kg/m^3 so
    1.29V = (mass of helium + mass of cargo)

    mass of helium = density of helium (.179) X volume

    so 1.29V - .179(V) = mass of cargo
    V for a sphere = 4/3 (pi) (r)^3 = 1663.2

    plug that in and I get 1847.8 for the mass, which is WRONG
    strangely if I divide that by 2 I get the right answer though... 924, which rounded down would be 920, but I have no idea why id divide it by 2..

    someone help please (i hope this makes some sense, I dont think Im making sense to myself, lol)
  2. jcsd
  3. Nov 12, 2005 #2


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    Science Advisor

    You forgot to subtract off the 930 kg weight of the balloon skin and structure!!
  4. Nov 12, 2005 #3
    Oh crap, you're right

    Wow I feel stupid. Thanks Halls of Ivy (I'm going to go hide now LOL)
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