Burning fuel and a motor's efficiency

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AI Thread Summary
To calculate the efficiency of a motor burning 20 liters of fuel per hour with a combustion heat of 6.6E6 cal/liter and producing 40 Hp, the power output is determined to be 107,424,000 Joules per hour. The total energy supplied by the fuel is 31,533,684 Joules per hour after converting calories to Joules. The discussion highlights a misunderstanding regarding the energy supplied versus the motor's output. The efficiency can be calculated by comparing the output power to the energy supplied by the fuel. The conversation emphasizes the importance of accurate unit conversions in determining motor efficiency.
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Homework Statement


A motor burns 20 liter per hour. the fuel's combustion heat is 6.6E6[cal/liter] (i don't know if it's kcal or cal, but i assume it's cal). the motor produces 40 [Hp], what's the efficiency.

Homework Equations


1[Hp]=746[W]. 1[W]=[Joule/sec]
1[cal]=4.186[Joule]

The Attempt at a Solution


40[Hp]x746x3600=107,424,000[Joule/hour]
20[liter]x6.6E6[cal/liter]=13.2E7[cal/hour]
13.2E7[cal/hour]/4.186=31,533,684[Joule/hour]
The fuel supplies less power the the motor's output. not true
 
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1[cal]=4.186[Joule]

13.2E7[cal/hour]/4.186...
 
Thanks
 
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