Business Calculus Minimize Inv Cost

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Homework Statement


A sporting goods store sells 135 pool tables per year. It costs $10 to store one pool table for a year. To reorder, there is a fixed cost of $27 per shipment plus $18 for each pool table. How many times per year should the store order pool tables, and in what lot size, in order to minimize inventory costs?[/B]

Homework Equations


Yearly Carrying Cost = $10 (x/2) -> 5x
Yearly Reorder Cost = 27+18x(135/x)

The Attempt at a Solution


C(x) = 5x + (45x) (135/x)

Am I doing this right? I can't tell since I messed up when I was taking my notes... I am not sure how to continue. I know I have to find the derivative after, but I don't know how I would condense X
 
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KevinJay said:

Homework Statement


A sporting goods store sells 135 pool tables per year. It costs $10 to store one pool table for a year. To reorder, there is a fixed cost of $27 per shipment plus $18 for each pool table. How many times per year should the store order pool tables, and in what lot size, in order to minimize inventory costs?[/B]

Homework Equations


Yearly Carrying Cost = $10 (x/2) -> 5x
Yearly Reorder Cost = 27+18x(135/x)
It's always a good idea to explicitly state what any variable represents. For this problem 'x' could be the number of pool tables to order in a shipment, or it could be the number of times per year to reorder.
KevinJay said:

The Attempt at a Solution


C(x) = 5x + (45x) (135/x)

Am I doing this right? I can't tell since I messed up when I was taking my notes... I am not sure how to continue. I know I have to find the derivative after, but I don't know how I would condense X
 
KevinJay said:

Homework Statement


A sporting goods store sells 135 pool tables per year. It costs $10 to store one pool table for a year. To reorder, there is a fixed cost of $27 per shipment plus $18 for each pool table. How many times per year should the store order pool tables, and in what lot size, in order to minimize inventory costs?[/B]

Homework Equations


Yearly Carrying Cost = $10 (x/2) -> 5x
Yearly Reorder Cost = 27+18x(135/x)

The Attempt at a Solution


C(x) = 5x + (45x) (135/x)

Am I doing this right? I can't tell since I messed up when I was taking my notes... I am not sure how to continue. I know I have to find the derivative after, but I don't know how I would condense X

This is a standard Economic Order Quantity (EOQ) model, as found in any Operations Research textbook, or on-line; see, eg.,
https://en.wikipedia.org/wiki/Economic_order_quantity .
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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