But overall, you've got the right idea.

AI Thread Summary
A roller coaster illustrates the law of conservation of energy by converting potential energy into kinetic energy as it descends. At the highest point, the potential energy is at its maximum, which then transforms into kinetic energy as the coaster moves downward. The discussion highlights that minimal friction is crucial for this energy transfer, as friction can impede the conversion process. The relationship between potential energy and kinetic energy is emphasized, reinforcing that the total energy remains constant throughout the ride. Understanding these principles is essential for grasping the mechanics of roller coasters.
physicsman2
Messages
139
Reaction score
0

Homework Statement


How does a roller coaster demonstrate the law of conservation of energy by the transfer of potential energy to kinetic energy


Homework Equations


KE=PE


The Attempt at a Solution


i believe that as the roller coaster descends down the hill the potential energy changes into kinetic energy where the amount of potential energy at the top of the hill is equal to the kinetic energy just as it hits the bottom

i think this is right but i have a feeling there is more to it than this
 
Physics news on Phys.org
Sounds right to me.

The key element of a roller-coaster is in its name even Rolling. Coasting. Low frictional loss activities, because of course frictional loss is the enemy of the pure translation of Potential energy to Kinetic motion.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top