Calc Forces on Pulleys: 200N, 300N Masses, No Friction

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The discussion focuses on calculating the tensions FT1 and FT2 in a pulley system with weights of 200 N and 300 N, assuming no friction and negligible pulley mass. It highlights that mass B rises while mass A falls, leading to the conclusion that the forces on pulley P2 are represented as 2FT2 acting upward and FT1 acting downward. The conversation also addresses the relationship between the distances moved by masses A and B, indicating that if A lowers by x meters, B rises by the same distance. Additionally, it explores the implications of their speeds, suggesting that the acceleration of B is directly related to that of A. Understanding these dynamics is crucial for solving the problem accurately.
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Homework Statement
In Figure 3-25, the weights of the objects are 200 N and 300 N. It is considered
that the pulleys have no friction and that their masses are negligible. Pulley
P1 has a stationary axis, the P2 pulley can raise or lower freely.
Calculate the tensions FT1 and FT2, as well as the acceleration of each body
Relevant Equations
F=m a
Homework Statement: In Figure 3-25, the weights of the objects are 200 N and 300 N. It is considered
that the pulleys have no friction and that their masses are negligible. Pulley
P1 has a stationary axis, the P2 pulley can raise or lower freely.
Calculate the tensions FT1 and FT2, as well as the acceleration of each body
Homework Equations: F=m a

this problem is in the schaum physics book 10 ed 3.37 and says something like this:

Mass B rises and mass A falls. This can be seen if it is observed that the forces acting on the P2 pulley are 2FT2 up and FT1 down

WHY does the forces acting on P2 pulley are 2FT2?

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You want to write out your relevant equation to show this.
How far does B go up if A lowers ##x## m ?
So how fast does B go up when A lowers with speed ##v## m/s?
What does that mean for the acceleration of B wrt that of A ?
 
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