Calculate Arc Length of Hypocycloid Function | Homework Help

DarkSamurai
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Homework Statement


Find the arc length of r(t) = cos(t)^3 i + sin(t)^3 j
from t = 0 to t = 2 * Pi

It's a hypocycloid that's four cusped.

Homework Equations


s = \int\sqrt{x'^2 + y'^2}


The Attempt at a Solution


x = cos(t)^3
y = sin(t)^3

x' = -3cos(t)^2*sin(t)
y' = 3sin(t)^2*cos(t)

\sqrt{x'^2 + y'^2} = 3* \sqrt{cos(t)^4*sin(t)^2 + sin(t)^4*cos(t)^2}

That simplifies to s = \int 3*\sqrt{1}

So the answer is 6*Pi, but for some reason Maple throws out 6.
 
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The radical doesn't simplify to 1. Check that again.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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