Calculate Average Acceleration for Kinematics Question

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The discussion centers on calculating the average acceleration of a roller coaster cart reaching the bottom of a hill, using kinematic equations. The initial velocity is 0 m/s, the final velocity is 46.5 m/s, the height of the hill is 110 m, and the time taken is 5.3 seconds. The correct average acceleration is calculated as 8.8 m/s² using the formula a = Δv / t, while an alternative calculation using Vf² = Vi² + 2ad yields 9.8 m/s² due to incorrect distance input. The discrepancy arises because the second formula requires the distance traveled along the hill, not the vertical height. Understanding the direction of velocity and acceleration is crucial for accurate calculations.
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Homework Statement


This is a question from the June 2009 Regents. The question asks what is the average acceleration of a roller coaster cart as it reaches the bottom of a hill. You know that
Vi = 0 m/s (The cart starts from rest from the top of a hill)
Vf = 46.5 m/s (velocity at bottom of hill)
d = 110 m (This is the height of the hill)
t = 5.3 s (Time it takes for it to start from rest and reach the bottom of the hill)

Homework Equations


The Kinematics equations on the reference table:
a = Δv / t

d = (Vi)t + 1/2at2

Vf2 = Vi2 + 2ad

Where Vi is initial velocity, and Vf is final velocity.

The Attempt at a Solution



According to the answer key:
a = Δv / t
a = (46.5m/s) / 5.3 s
and a = 8.8 m/s2

However, I did Vf2 = Vi2 + 2ad

I plugged in all the correct numbers and got 9.8m/s2

Why isn't my answer valid/ Why do the two formulas yield different answers?

Thank you.
 
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AlbanyHS said:
However, I did Vf2 = Vi2 + 2ad

I plugged in all the correct numbers and got 9.8m/s2

Why isn't my answer valid/ Why do the two formulas yield different answers?
Realize that the velocity and acceleration are parallel to the hill surface, not straight down. If you use that formula, you need d = distance traveled down the hill, not the height of the hill.
 
Ah, I see. Thank you for clarifying.
 
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