Calculate Average Energy Use/Month

AI Thread Summary
The discussion focuses on calculating average energy use per month based on a power bill. A bill of $27.00 at a rate of 6.3 cents per kilowatt hour results in an average energy consumption of approximately 595.24 Joules per second. The conversation then shifts to determining the charge drawn by a 120 V air-conditioner, which accounts for about two-thirds of the total energy usage. This leads to a calculation of approximately 3.21 Coulombs per second for the air-conditioner. The calculations are confirmed to be accurate, with a note on the importance of significant figures.
NickCherryJiggz
Messages
3
Reaction score
0
I'm helping a friend with this question and wanted to make sure I was doing it correctly...

Suppose your local power company charges 6.3 cents per kilowatt hour and your most recent bill came to $27.00. How much energy, on average, did you use (in Joules) per second last month? Assume that the billing period covered 30 days.

$27.00/($0.063/kilowatt hour) = 428.571428... kilowatt hours

428.57... * (3.6 x 10^6) = (1.5428571428571 * 10^9 Joules)/month = M

M / (30 * 24 * 60 * 60) = 595.23809523808 Joules/second

Thanks for the help!
 
Physics news on Phys.org
It's okay.U may want to learn the concept of significant figures,though...:rolleyes:

Daniel.
 
Thank you, Daniel...Sorry about the sigdigs.
I know these are just silly conversions for the most part, but could someone please verify the second half of the question as well?

Now pretend that roughly 2/3 of the energy usage last month was a result of a 120 V air-conditioner, how many Coulombs of charge per second did that air-conditioner draw?

595.24... * 2/3 = 396.83...J/s
V = J/C
120 Volts = (396.83... J/s) / (Coulombs/s)
3.21 Coulombs/second
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top