Calculate Block Friction: 2-kg Block & Horizontal Spring

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A 2-kg block is propelled by a compressed spring with a spring constant of 120 N/m, sliding 47 cm before stopping. The work done by the spring is calculated using the equation W = 0.5kx^2, resulting in a force of 4.136 N. To find the coefficient of kinetic friction (μk), the normal force (F(n)) must be determined, which equals the block's weight due to gravity. The relationship between the frictional force and the normal force is expressed as F = μk * F(n). The discussion emphasizes understanding the forces acting on the block and how to calculate work done by friction.
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Homework Statement


A 2- kg block rests against one end of a horizontal spring which is compressed by 18 cm. When the spring is released, the spring forces the block to slide across a table top. It stops 47 cm from where you released it. The spring constant k is equal to 120 N/m. Calculate the constant of kinetic friction μk between the block and the table.


Homework Equations


W=.5kx^2
W=Fd


The Attempt at a Solution


I used the two equation above to find that F=4.136N

Somebody suggested I should put this into the equation F=μk*F(n), but I don't know how to find F(n). Any help?
 
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The table is horizontal. Consider the vertical forces acting on the block.
 
Doc Al said:
The table is horizontal. Consider the vertical forces acting on the block.

Okay, gravity? How do I apply that to this problem?
 
Gravity is one of the forces on the block.

Answer this: A block sits on the table. What normal force must the table exert on the block?
 
anastasiaw said:
Okay, gravity? How do I apply that to this problem?

Okay I got it -- F(n) is the normal force... the weight of the object. Thanks.
 
That's it.
 
Consider the work done by frictional force. It will be equal to?
μk x Normal Force = ?
 
anirudh215 said:
μk x Normal Force = ?
That's the friction force. How do you find work?
 
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