Calculate Change in Height Using Angle and Distance Traveled

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To calculate the change in height, the correct method is to multiply the distance traveled (0.797 m) by the sine of the angle (3.11 degrees), which is accurate. The discussion confirms that this approach is valid for determining height. Additionally, there is a request for a formula to calculate the percentage of elastic energy not converted to kinetic energy. The community provides reassurance and support for the calculations being performed. Overall, the conversation focuses on confirming the height calculation and seeking further assistance with energy conversion formulas.
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I'm trying to determine change in height using my angle that I determined to be 3.11 degrees and the distance traveled by cart which is 0.797 m. I multiplied 0.797 by Sin 3.11 to find the height but I have no idea if that is right. Any help would be appreciated since we didn't go through this in class and this is for a lab. After this I also need to determine what percent of elastic energy was not converted to kinetic. Is there a formula for that?


Thank you in advance for your help!
 
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Welcome to PF, miodoll!
 
YES! That's what I did! Does that make sense? Did I do it right or am I completely off?

And thank you for the welcoming!
 
Yes, it is correct! Most welcome.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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