Calculate Earth's Orbital Period Around the Sun | Gravitational Problem

  • Thread starter Thread starter Demin
  • Start date Start date
  • Tags Tags
    Gravitational
AI Thread Summary
The discussion revolves around calculating Earth's orbital period around the Sun using the given masses and distance. The relevant equation T^2 = kr^3 is mentioned, indicating a relationship between the orbital period and the radius. The user notes that they can derive the period by equating gravitational force to centripetal force, assuming a circular orbit. They express difficulty in using angular velocity (omega) since the answer needs to be in seconds rather than radians. The focus remains on applying gravitational principles to determine the orbital period accurately.
Demin
Messages
4
Reaction score
0

Homework Statement



Whats the Earth's orbital period around the sun if mE=5.98x10^24kg , mS =2x10^30kg,
r = 1.5x10^11


Homework Equations


T^2= kr^3


The Attempt at a Solution



i can figure out the period easily w/ 2 radii + 1 period
 
Physics news on Phys.org
Assuming that the orbit is circular, use grav force on Earth due to sun is equal to the centrpetal force. Also, T=2pi/omega.
 
cant use omega ,,answer has to be in sec not rads :(
 
That's why I'd given the relation between T and omega.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top