Calculate Electrostatic Force Between Two Plates

AI Thread Summary
To calculate the electrostatic force between two plates, one must consider the surface charge density and the electric field generated by each plate. Given the plates' area of 2 sq/m, a separation of 0.006 m, and a potential difference of 10,000 volts, the charge on the plates can be determined using the equation Q = AeV/d. The force exerted on one plate by the electric field of the other can be expressed as F = eAV^2/(2d^2). It's important to note that this calculation assumes the plates are infinite, and practical applications may require a correction factor.
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Hello, first post here. I hope this is in the right section.
I have spent an hour or so surfing the net and could not figure this out (i am bad at physics).

How do you figure out the electrostatic force attracting two plates? The plates are 2sq/m, have a 0.006m spacing, and have 10000 volts of potential difference.
 
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Welcome. Since you said you were “bad” at Physics, I’m trying to give you a detailed solution.

When a voltage V is applied across the plates, suppose the plates receive charges +Q and -Q. The surface charge density on the plates are +s and –s, where s=Q/A. If the plates were infinite in extent, then each would produce an electric field of magnitude
s/(2e) = Q/(2Ae) --(1), where I’m writing e for epsilon_naught. Let d be the separation between the plates.

The sum of the fields of both the plates E = Q/(Ae) and V=E*d
=> Q = AeV/d --(2).

So, force on one plate due to field of other = Q*field = Q*Q/(2Ae) (from 1)
= eAV^2/(2d^2) (from 2).

Note that the electric field of each plate has been calculated for the case when each plate in infinite in extent. In practice, some correction factor is introduced.
 
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