Calculate EMF of Cell with 10 ohms & 15 ohms Resistors

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The discussion centers on a physics problem involving a cell with negligible resistance connected in series with a microammeter and two resistors of 10 ohms and 15 ohms. The total resistance is calculated as 25 ohms. Given a current of 200 microamperes (uA), the EMF of the cell can be determined using the formula EMF = iR. Substituting the values, the EMF is calculated to be 5 volts. The user expresses gratitude for any assistance provided.
Chris-is-stuck
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hi I am sorry this is probably going to seem very easy to all you viewers but up to this point I've had to teach myself physics because i had no teacher. i still got a* at gcse though :-p

the question is: A cell of negligible resistance is connected in a series with a microammeter of negligible resistance and two resistores of 10 ohms and 15 ohms. The current is 200 uA.

Calculate the EMF of the cell.

thanks a lot to anyone to helps me with this, cya later.


(jsut read rules sorry if I've broken any)
 
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The total resistance is R=10+15=25 ohms. Therefore:

EMF = iR

You have i, so...
 

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