Calculate Energy Released in 2/1H + 3/1H -> 4/2He + 1/0n Reaction

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To calculate the energy released in the reaction 2/1H + 3/1H -> 4/2He + 1/0n, one must first determine the mass difference between the reactants and products. The masses of the involved particles can be found in textbooks or online resources. The mass defect should be evaluated in atomic mass units (amu), which can then be converted to energy using the conversion factor of 931 MeV/amu. This calculation will yield the energy released in the reaction. Understanding these steps is crucial for accurately determining the energy output of nuclear reactions.
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Calculate the energy (in Mev's) released in the reaction: 2/1H + 3/1H ->4/2He + 1/0n + E
and i know 1 amu = 931 Mev
 
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Calculate the difference in mass between the reactants and the products, then convert that mass difference into energy units.

- Warren
 
Either the book where u've taken that reaction or the internet has to have the rest masses of those 4 partices.

Daniel.

P.S.Evaluate the mass defect in amu-s and then simply multiply the result by 931MeV/amu.
 
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