Calculate Force Needed to Stretch Spring 48cm: 270 N/m

AI Thread Summary
To calculate the force needed to stretch a spring 48 cm with a spring constant of 270 N/m, Hooke's Law should be applied, which states that force equals the spring constant multiplied by the displacement (F = kx). The user initially attempted to use the potential energy formula (1/2 kx^2), which is incorrect for finding the force directly. The correct calculation involves converting 48 cm to meters (0.48 m) and then multiplying by the spring constant. The resulting force needed to stretch the spring is 129.6 N. Understanding the appropriate formula is crucial for solving this problem accurately.
ross moldvoer
Messages
16
Reaction score
0

Homework Statement


What force is necessary to stretch a spring 48 cm, if the spring constant is 270 N/m?

Homework Equations



1/2kx^2

The Attempt at a Solution


tried plugging everything into equation and got 31 but it is wrong. Any help would be greatly appreciated
 
Physics news on Phys.org
What units came out of your attempt to plug in value to that equation? Did you check to see that they matched what you're looking for?

Look for a more relevant Relevant equation. Hint: Hooke's Law.
 
The quantity you're looking for is force. The quantity your equation gives you is?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top