Calculate Friction Coefficient Using Pulleys and Mass

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To calculate the coefficient of friction for a mass at rest on a horizontal plane connected to a suspended mass via a pulley, the correct formula is M(1)a(coefficient of friction) = M(2)(g-a). The user initially miscalculated the coefficient, obtaining an implausibly high value of 7.5171. Upon clarification, it was noted that the system starts at rest and the suspended mass is released, resulting in an acceleration of 0.6525 m/s². This acceleration should be used to accurately determine the coefficient of friction. Understanding the initial conditions and proper application of the formula is crucial for correct calculations.
Chaotic Boredom
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Alright, I know I have this stuff somewhere at school, but unfortunately, I can't leave it till tom.

A mass is at rest on a horizontal plane, and is attached by a second mass that is threaded through a pulley and is suspended in the air. What is the coefficient of friction?

The formula I've been using is

M(1)a(coefficient of friction) = M(2) (g-a)
(sorry about the horrible representation)

rearranged into this:

M(2) (g-a) = (coefficient of friction)
M(1)a

where a= acceleration
M= mass
g = gravity = 9.81

Unfortunately, upon plugging in my numbers from the experiment, I keep getting 7.5171...for the coefficient of gravity...which to me seems impossibly high!
 
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The system is at rest, so what's acceleration supposed to be?

cookiemonster
 
Oops, forgot to mention that the system BEGINS at rest and then the suspended mass is released, hence the acceleration...wow, I feel dumber already! :rolleyes:

Acceleration was 0.6525 m/s(squared)
 
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