Calculate Friction: Get Friction Coefficients Help

  • Thread starter Thread starter JCCol
  • Start date Start date
  • Tags Tags
    Friction
AI Thread Summary
Calculating friction coefficients can be achieved using the formula μ = F/N, where F is the frictional force and N is the normal force. It's important to note that the normal force, R, acts perpendicular to the surface, and R = mg is applicable only on horizontal surfaces. For energy-based calculations, the work done by friction can be expressed as w = xRμ, leading to μ = w/(xR). Different methods exist for determining the coefficient of friction based on specific scenarios. Providing a specific example could help clarify any difficulties encountered in the calculations.
JCCol
Messages
25
Reaction score
0
I was wondering if someone could help me with calculating friction. I just don't understand how to get the friction coefficents. I was hoping someone could help me or redirect me to another post if this is a repost.
 
Physics news on Phys.org
there is a table for friction coefficients. but if you have kinetic friction and have the normal force and the force of the friction then you can do: force friction/normal force = Uk. my physics might be a bit rusty =/
 
Last edited:
Indeed quadruple is correct, if you are able to obtain the firctional force and the normal reaction force, all you need to do is rearrange to give;

\mu = \frac{R}{F}

Note that R always acts perpendicular to the surface R = mg only holds when the surface is horizontal, otherwise you are required to resolve the force of gravity to perpendicular to the surface.

Alternatively, if you are working with energy, the work done by a frictional force is given by w = xR\mu, where x is the displacement, thus the coefficient of friction is given by;

\mu = \frac{w}{xR}

There are many ways to obtain the coefficient of friction, depending on the circumstances in which it occurs. Perhaps, you could post a specific example of the type of question you are have difficulties with.
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top