Calculate Heat for Melting 10kg Ice Block

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To calculate the heat energy required to melt a 10 kg block of ice at 0 degrees Celsius into liquid water at the same temperature, the correct formula is Q = mL, where m is the mass and L is the latent heat of fusion. The latent heat of fusion for water is 3.34 x 10^5 J/kg. Using this formula, the total heat energy required is Q = 10 kg * 3.34 x 10^5 J/kg, resulting in 3.34 x 10^6 J. It is important to note that during the phase change, the temperature remains constant, and thus the initial equation used was incorrect. Understanding the distinction between temperature change and phase change is crucial in thermodynamics calculations.
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Homework Statement


Calculate the amount of heat energy required to melt a 10 Kg block of ice at 0 degrees C into liquid water at 0 degrees C. The latent heat of fusion for water is 3.34 * 10to the 5

Homework Equations



Q = mc(change in temperature)

The Attempt at a Solution



Q = (10)(3.34 * 10to the 5)(0)
Q= 0
 
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That is not the equation for thermal energy involving latent heat of fusion.
 
that is exactly what the question said...Actualy therre is a typo I'll edit it
 
The ice is undergoing a phase change here (from ice at 0 degrees to water at 0 degrees). In this situation, there is no change in temperature even though thermal energy is being generated. The equation you are using is not the one you need for this. You need Q=mL, where m is the mass of the ice, and L is the latent heat (of fusion in this case). Look it up.
 
thankyou!
 
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