Calculate Height of Object in 9 secs

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To calculate the height of an object launched and landing after 9 seconds, the key is understanding that the time taken to ascend equals the time taken to descend. The total time of 9 seconds means the object spends 4.5 seconds going up and 4.5 seconds coming down. Using the kinematic equations for constant acceleration, particularly considering gravity's acceleration of approximately 9.8 m/s², allows for the calculation of maximum height. The formula to use is h = 0.5 * g * t², where h is height, g is gravity, and t is the time of ascent. This approach simplifies the problem and leads to the solution efficiently.
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I need help. I need to know how high an object goes if launched, travels up and back down, and lands 9 seconds later. I remember that in a vacuum, the travel time up equals the travel time down, but what is the equation?
 
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The only thing you need to know, other than some basic algebra, is that the acceleration due to gravity is ~9.8 m/s2. Think about what that unit really means and it should be easy to solve.
 
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Hi charles7! Welcome to PF! :wink:

Use the standard constant acceleration equations. :smile:​
 

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