Calculate Magnitude & Angle of Clock's Vector Displacement

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The discussion focuses on calculating the magnitude and angle of the minute hand's displacement on a clock for specific time intervals. Participants clarify that the displacement for each interval differs due to the distinct positions of the minute hand. For the first interval, from a quarter past to half past, the magnitude and angle need to be calculated based on the hand's movement from the 3 to the 6 position. The confusion arises from assuming that the displacement remains constant across different intervals. Accurate vector representation and calculations are essential for determining the correct displacement values.
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The minute hand of a wall clock measures 12 cm from its tip to the axis about which it rotates. The magnitude and angle of the displacement vector of the tip are to be determined for three time intervals. What are the (a) magnitude and (b) angle from a quarter after the hour to half past, the (c) magnitude and (d) angle for the next half hour, and the (e) magnitude and (f) angle for the hour after that? Give all angles as positive values measured counterclockwise from the +x direction (to the right, or 3 o'clock).

I thought that the answer from (a) should be the same for (c) as (a) would be the square root of .12^2+.12^2 . Apparently its not. Any help would be appreciated. Doing vectors on clocks confuses me.
 
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Are you drawing the vectors out?

Part (c) is asking for the next half hour. Part (a) involved a quarter hour. If the minute hand is at the six, and then goes to the 12, what is the displacement? It won't be the same as (a).
 
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