Calculate Moment of Inertia About Y-Axis | Direct Integration Method

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Homework Statement



Determine by direct integration the moment of inertia about the y-axis in the figure shown.

Homework Equations


See Iy on attached.
Equation for curve also on attached.


The Attempt at a Solution


My answer didn't include pi, and the answer apparently does. I'm trying to do this via a double integral as opposed to using one integral and doing something funky. My problem I THINK is in finding dA.
 

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You are right. There is no "\pi" in the solution.

The moment of inertia of that figure, about the y-axis is
\int_{x=0}^a\int_{y= -b\sqrt{1-\frac{x^2}{a^2}}}^{b\sqrt{1-\frac{x^2}{a^2}}} y dydx
That's easy to integrate and has no "\pi".
 
Hmm - that's what I thought. In fact, I think that's the exact integral that I had. I'll give it another go. Thanks!
 
I lied - that's a y^2, not just a y in the integral. The answer is pi*a*(b^3)/8...Still no luck though.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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