Calculate Net Work Done by Fpush, Fgrav, Fnormal - 5N, 5m

  • Thread starter sundeepsingh
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In summary, a book is pushed up a ramp by a force and the net work done by:a. Fpush is 25 Jb. Fgrav is mgsin@ * 5c. Fnormal is mgcos@ * 0.5In regards to the tug of war question, if team A applies a force of 1100 Newton to pull team B towards them in a distance of 2 meters, the work done by team A would be:W = Fd\cos\theta = 1100 * 2 * \cos 0 = 2200 J.
  • #1
sundeepsingh
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A book is pushed up a ramp by a force. Calculate the net work done by :

a. Fpush
b. Fgrav
c. Fnormal

Let fnet = 5 Newtons and displacement of the object be 5 m up the ramp,
so the net work done by Fpush = 5 * 5 = 25 J. is the Work net by grav = mgsin@ * 5? and net work by Fnormal = mgcos@ * 0.5? is the work of gravity negative and Fnormal positive? Kindly guide me to the correct answers. Thanks
 
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  • #2
Fpush is right. For part b and part c. You do need to understand that the work is done only by multiplying the force and the distance parallel to the direction of the force.
 
  • #3
sundeepsingh said:
A book is pushed up a ramp by a force. Calculate the net work done by :

a. Fpush
b. Fgrav
c. Fnormal

Let fnet = 5 Newtons and displacement of the object be 5 m up the ramp,
so the net work done by Fpush = 5 * 5 = 25 J. is the Work net by grav = mgsin@ * 5? and net work by Fnormal = mgcos@ * 0.5? is the work of gravity negative and Fnormal positive? Kindly guide me to the correct answers. Thanks
Keep in mind that Work is a dot product of the force and displacement vectors. So:

[tex]W = Fd\cos\theta[/tex]

So for c. what is the angle between the force and the displacement? What is the cos of that angle?

For b, what is the angle between the gravitational force and the displacement in terms of [itex]\alpha[/itex], the angle of the ramp above the horizontal? (your answer is right here, but the analysis is not clear).

You have it right for a.

AM
 
  • #4
could you please answer this?
During a tug of war, team A pulls on team B by applying a force of 1100 Newton to the rope between them. How much work does team A do if they pull team B toward them in a distance of 2 meters?
 
  • #5
eureka360 said:
could you please answer this?
During a tug of war, team A pulls on team B by applying a force of 1100 Newton to the rope between them. How much work does team A do if they pull team B toward them in a distance of 2 meters?

The answer to your question is in Andrew Mason's post above. :smile:
 

Related to Calculate Net Work Done by Fpush, Fgrav, Fnormal - 5N, 5m

What is net work?

Net work refers to the total amount of energy transferred by a force when moving an object over a certain distance. It takes into account both the magnitude and direction of the force.

What is the formula for calculating net work?

The formula for calculating net work is W = F * d * cosθ, where W represents work, F is the applied force, d is the displacement, and θ is the angle between the force and displacement vectors.

How do you calculate net work when multiple forces are involved?

To calculate net work when multiple forces are involved, you must first calculate the work done by each individual force using the formula W = F * d * cosθ. Then, you can add all of the individual work values together to find the total net work.

What are the units for net work?

The units for net work are joules (J) in the SI system. However, it can also be expressed in other units such as foot-pounds (ft-lb) or calories (cal).

How does the direction of the force affect the net work done?

The direction of the force is taken into account in the net work formula as it is represented by the cosine of the angle between the force and displacement vectors. If the force and displacement are in the same direction (θ = 0), then the net work will be positive. If they are in opposite directions (θ = 180), the net work will be negative. If the force is perpendicular to the displacement (θ = 90), then the net work will be zero.

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