Calculate Pressure Due to Heated Water in Tank

AI Thread Summary
Calculating pressure in a closed tank with heated water involves considering both the tank's material properties and the water's thermal expansion. For a full tank, the pressure increases as water expands, potentially leading to tank failure if the expansion exceeds the tank's capacity. In a half-full tank, the presence of gas or vapor can affect pressure dynamics, as gas compressibility and solubility in water play significant roles. Understanding concepts like volumetric expansion and bulk modulus is crucial for accurate calculations. Proper safety measures, such as maintaining ullage, are essential to prevent dangerous situations like bursts or explosions.
Muhad
Messages
2
Reaction score
0
Hello guys,

I have problem to calculation pressure due to heated water in a closed tank.
1. Tank with full of water.
2. Tank with half of water.

Does anyone has idea?
Thanks a million.
 
Engineering news on Phys.org
Is this homework? Did you attempt a solution?
 
It is part of study that has been carried out
 
You didn't provide anywhere close to enough information for us to be able to help you. Heck, other than asking for help, you didn't even ask any questions about the issue you are trying to investigate!
 
Welcome to PF.
Muhad said:
I have problem to calculation pressure due to heated water in a closed tank.
1. Tank with full of water.
2. Tank with half of water.
Does anyone has idea?
Can we assume external pressure is atmospheric and that water temperature = tank temperature.
Assume water temperature is liquid and between 0°C and 100°C, or you could have an ice burst or a steam explosion.

Consider case 1.
Assume tank contains no gas bubbles.
What material is the tank made from? Tank expands in three dimensions as it gets hotter. What is expansion coefficient and Young's modulus of tank and of water?
Water in tank expands as it gets hotter. If the water volume expands faster than the tank volume then the water will be compressed and the tank stretched. There will be a pressure in the tank due to those relative expansions and pressures. At some point the tank will burst.

Consider case 2.
Half full of water and half full of what else, air, water vapour or another liquid such as oil?
If other half is a gas then the gas will be compressed or rarefied to make up for the differential expansion of tank and liquid. The solubility of gas in water may be important.

Ullage is not always bad, it is essential to safety. Look up the word ullage.
See also; https://en.wikipedia.org/wiki/Ullage#Industrial_use
 
In case 1, I think they want you to assume that the tank volume does not change. You are starting with pure liquid. Are you familiar with the concepts of coefficient of volumetric expansion and bulk modulus?

Chet
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top