- #1
The-Exiled
- 19
- 0
Homework Statement
The diameter of the 5th and 15th bright ring formed by sodium light (wavelength = 589.3nm) are 2.303mm and 4.134mm respectively. Calculate the radius of curvature.
Homework Equations
DON'T ASSUME THAT THE RINGS ARE PERFECTLY CENTRED
(I assume that means that the radius of the rings can't be obtained by simply dividing the diameter by 2)
The Attempt at a Solution
I am not sure how to start finding the radius of the rings or if I need it at all? I know there is a [tex]\pi[/tex] phase change and hence the constructive interference is when
2 x [distance in air] = (m + 0.5)[tex]\lambda[/tex].
I've tried finding the ratios of diameters for some reason, just to see if it lead to anything... It didn't... Can anyone help me please?
Thank you very much