Calculate Reaction Forces at B & D: Beam Bending Homework

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The discussion focuses on calculating the reaction forces at points B and D in a beam bending problem. The initial attempt at solving involves summing vertical forces and applying moment equations, but the user receives feedback indicating errors in their moment calculations, particularly regarding the signs and the application of distributed loads. Clarifications are provided on how to correctly determine the moments about point D, emphasizing the importance of the moment arm and the direction of moments. The user expresses confusion about the sign conventions for moments, which are explained as being consistent with a right-hand system where counterclockwise moments are positive. Overall, the thread highlights the critical aspects of correctly applying static equilibrium principles in beam analysis.
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Homework Statement



Calculate the reaction forces at B and D

See attached jpeg.

The Attempt at a Solution



sum of vertical forces

By + Dy = 7 + (9*5)

Do I then solve for the moment about D or A or B?

for moment about D i have: -Dy -7 -(9*5)+9By+(12*2)=0

is this correct, please explain to me the process of and how I should go about these problems

Any advice is appreciated, thankyou.
 

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The moment equation you have written is incorrect. For example, what is the moment of the 7 kN force about D? Remember, the sign of the moment is important. The moment of the distributed load is also incorrect. I don't know why you are multiplying the applied moment of 12 kNm by 2.
 
SteamKing said:
The moment equation you have written is incorrect. For example, what is the moment of the 7 kN force about D? Remember, the sign of the moment is important. The moment of the distributed load is also incorrect. I don't know why you are multiplying the applied moment of 12 kNm by 2.

When the moment is clockwise to the left of the point it is positive?

moment about D:

9By +12 - (9*5*2.5) -(7*4) = 0

Is that correct now?
 
On the moment of the distributed load, remember the center of the load must be taken about point D. Check your moment arm.
 
SteamKing said:
On the moment of the distributed load, remember the center of the load must be taken about point D. Check your moment arm.


9By +12 - (9*5*6.5) -(7*4) = 0

By= 34.28

I'm am still a bit unclear on the moments when they are positive and negative, is what I said before correct, when they are to the left of the point and clockwise , they are positive?
 
The convention chosen doesn't matter, as long as it is consistently applied. I use the convention where the horizontal direction is positive to the right, vertical is positive upward, and the counterclockwise moment about the origin is positive. This is a right-hand system, and it is used later on in other areas of physics.
 
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