- #1
RingNebula57
- 56
- 2
Hello everyone! I found in my textbook that in order to calculate the pressure experienced by the surface of a long straight solenoid with ##n## turns per unit length and current ##I## we don't use the typical magnetic field ##B=\mu_0nI## on a loop of the coil , but a corrected magnetic field ##B=\frac{\mu_onI}{2}## which excludes the contribution or "self force" of the loop. How can I prove this formula? (to calculate the pressure is not a problem if I know the formula for ##B##). Furthermore, I saw that this factor ##"\frac{1}{2}"## is used in other cases also in which we have self-forces.