Calculate Speed for Parabolic Basketball Throw from 2.1m at 18°

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AI Thread Summary
To calculate the speed required for a basketball thrown from a height of 2.1m at an angle of 18° to reach a basket 11m away at a height of 2.6m, one should apply the principles of projectile motion. The key equations involve determining the horizontal and vertical components of the throw, factoring in gravitational acceleration. The initial speed can be derived from the range and height difference using kinematic equations. Starting with the basic projectile motion formulas will help in solving for the necessary speed. Understanding these concepts is crucial for finding the solution effectively.
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Homework Statement


A person throws a basketball at the basket from an altitude of 2.1m the basket is 11m away and at an altitude of 2.6m. The ball is thrown with an angle of 18°.


Homework Equations


what speed does the ball need to be thrown at so that it goes into the basket.


The Attempt at a Solution


Sorry guys, I really don't know how to start solving it. Any ideas?

thank you very much for your help
 
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Welcome to PF :smile:

I'll hazard a guess that your class has been studying constant acceleration and projectile motion. Start with the usual equations for that.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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