klm
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What is the tension in the string?
okay i have figured this much out,
Tsin(16.69) = m (v^2)/ r
T cos 16.69 -mg =0
i don't know how to solve for T though. i know it should be simple math, but i can't figure it out!
i have tried this
r(tsin 16.69) / v^2 = m
and Tcos16.69 / g = m
and then make them equal,
Tcos16.69 / g = r(Tsin16.69)/V^2
but now i am lost
okay i have figured this much out,
Tsin(16.69) = m (v^2)/ r
T cos 16.69 -mg =0
i don't know how to solve for T though. i know it should be simple math, but i can't figure it out!
i have tried this
r(tsin 16.69) / v^2 = m
and Tcos16.69 / g = m
and then make them equal,
Tcos16.69 / g = r(Tsin16.69)/V^2
but now i am lost