Calculate Tangential Speed of Yo-yo with Centripetal Acceleration of 289 m/s2

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To calculate the tangential speed of the yo-yo, use the formula for centripetal acceleration, a = v²/r, where a is the centripetal acceleration (289 m/s²) and r is the radius (0.78 m). Rearranging the formula gives v = √(a * r). Substituting the values, v = √(289 * 0.78), which results in a tangential speed of approximately 15.1 m/s. This calculation provides the necessary answer for the given physics problem.
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Hello! Usually I have my friend help me with physics questions but he is away on vacation and I don't want to bother him. Anyways, the question is:

A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 289 m/s (squared).
If the yo-yo's string is .78 m long, what is the yo-yo's tangential speed? Answer in units of m/s.
 
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Do you know the formula for centripetal acceleration? It is
a=\frac{v^2}{r}
v is the tangential speed and r is the radius.
 

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