Calculate the acceleration and the tension in the rope

AI Thread Summary
To calculate the acceleration and tension in the rope for the given system, the equations of motion must be applied to both masses, m1 and m2, considering the angles theta1 and theta2. The forces acting on each mass can be expressed as T - m1g sin(theta1) = m1a for mass m1 and m2g sin(theta2) - T = m2a for mass m2. By isolating the tension T and substituting the expressions, the acceleration can be determined. It is suggested to draw a free body diagram (FBD) for clarity and to simplify calculations. Understanding the forces parallel to the incline can also make solving the problem easier.
Leo194
Messages
3
Reaction score
0

Homework Statement


Calculate the acceleration and the tension in the rope. For your variables use "m1", "m2", "theta1", "theta2" and "g". Assume all surfaces are frictionless, and the pulley and rope are massless and frictionless.



http://www.webassign.net/userimages/48539?db=v4net






Homework Equations



Fne=ma, wight=ma

The Attempt at a Solution



((m2sin(theta2)-m1sin(theta1)/((m1+m2))(g)
 
Physics news on Phys.org
so, did you have a question about this situation?
 
yes, I am not sure how to find the acceleration and tension.
 
once you know the acceleration,
the Tension can be obtained by isolating
*either one* of the blocks
... "cutting the rope" allows T to be measured.
 
Try to draw the FBD of the two blocks.

Now as the surfaces are friction less

T - m1gsin(theta1) = m1a

and m2gsin(theta2) - T = m2a
 
are you aware that there is an arrow in fed ex? and y don't you try solving it in terms of force parallel? its much easier
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Newton's Second Law (Pulley Sustem)
Replies
3
Views
2K
Monkey accelerating up and down a rope
Replies
38
Views
4K
Falling mass, additionally accelerated by a rope
Replies
18
Views
1K
Problem with pulleys - two fixed and one movable
Replies
22
Views
370
Why body A has greater acceleration?
Replies
13
Views
1K
Acceleration of rising mass and tension in cord
Replies
33
Views
3K
Acceleration and Tension in Multiple Pulleys
Replies
7
Views
8K
I'm I on the right track? Tension question
Replies
21
Views
2K
How Does Nick's Acceleration Change When His Friend Pulls the Rope?
Replies
6
Views
4K
Tension on a Massive Rope: How to Calculate Tension at Different Points
Replies
11
Views
3K

Hot Threads

Recent Insights

Back
Top