Calculate the electric potential of a sphere

AI Thread Summary
The discussion revolves around calculating the electric potential of a charged metal sphere and a surrounding spherical shell. The inner sphere has a radius of 1 cm and a charge of 1 nC, while the shell has an inner radius of 2 cm and an outer radius of 3 cm, with a potential of 150 V at infinity. The calculated electric potential of the inner sphere is 600 V, and the total charge of the spherical shell is determined to be -0.5 nC. The negative charge of the shell is explained by applying Gauss's law and integrating the electric field to find potential differences. The approach to solving the problem is confirmed as correct by other participants in the discussion.
doktorwho
Messages
181
Reaction score
6

Homework Statement


A metal sphere of radius ##a=1cm## is charged with ##Q_a=1nC##. Around a sphere is placed a spherical shell of inner radius ##b=2cm## and outer radius ##c=3cm##. The electrical potential of the shell in refenrence to a point in the infinity is ##V=150V##. The spheres are in a vacuum. Calculate:
a) The electric potential of the inner sphere in reference to a point in the infinity
b) The total charge of the spherical shell

Homework Equations


3. The Attempt at a Solution [/B]
Im going to give you the results straight away so you can help me faster.
a) ##600V##
b) ##-0.5nC##
The first one i don't know how to start but the b) part i tried like this:
##V=\frac{Q}{4πξ_oR}## where ##R=C## and got 0.5 but i don't get the ##-## part. I don't understand this problem..Can you help?
 
Physics news on Phys.org
doktorwho said:

Homework Statement


A metal sphere of radius ##a=1cm## is charged with ##Q_a=1nC##. Around a sphere is placed a spherical shell of inner radius ##b=2cm## and outer radius ##c=3cm##. The electrical potential of the shell in refenrence to a point in the infinity is ##V=150V##. The spheres are in a vacuum. Calculate:
a) The electric potential of the inner sphere in reference to a point in the infinity
b) The total charge of the spherical shell

Homework Equations


3. The Attempt at a Solution [/B]
Im going to give you the results straight away so you can help me faster.
a) ##600V##
b) ##-0.5nC##
The first one i don't know how to start but the b) part i tried like this:
##V=\frac{Q}{4πξ_oR}## where ##R=C## and got 0.5 but i don't get the ##-## part. I don't understand this problem..Can you help?

Hi doktorwho! :oldsmile:

For (b) you calculated the total enclosed charge, which is indeed +0.5 nC. Since the inner sphere carries 1 nC, the outer spherical shell must have -0.5 nC.
 
  • Like
Likes doktorwho
If the sphere and the shell are made of metal (a conductor), the electrical potential is constant in them. Use Gauss's law to determine the electric field at different radii between the sphere and the outer shell, and then integrate to find the potential difference between the sphere and the shell.
 
  • Like
Likes doktorwho
hilbert2 said:
If the sphere and the shell are made of metal (a conductor), the electrical potential is constant in them. Use Gauss's law to determine the electric field at different radii between the sphere and the outer shell, and then integrate to find the potential difference between the sphere and the shell.
Can i do it like this?:
##V_a+∫Edl+V_c=V_{inner}##
Basically I am adding up the potential of the sphere at surface, the potential difference between point b and point a and the potential of the whole. Simply:
##V_b+V_c=V_{inner}## where i use the respective Q-s. Since the potential of the ##V_c=\frac{0.5}{4πε_or_c}## and the ##V_b## is proportional to ##V_c## ##V_b=2*\frac{3}{2}*V_c=450V## i get 600. Is this correct thinking?
 
^ yes, that seems to be correct.
 
  • Like
Likes doktorwho
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top