Calculate the electromotive force E

AI Thread Summary
The discussion focuses on demonstrating the relationship of electromotive force (emf) in an AC motor. Participants suggest using the equation E=BLVsinθ*N to calculate motional emf, emphasizing the role of Lorentz's force and Faraday's laws. There is a debate over the correct representation of the varying magnetic flux, with some advocating for a cosine function while others argue for a sine function. The consensus is that the chosen function for varying flux dictates the form of the emf equation. Overall, understanding these relationships is crucial for accurately demonstrating emf in AC motors.
bassi ali
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hi,
How can I demonstrate the relationship of the electromotive force of a motor AC
thank you
 

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bassi ali said:
hi,
How can I demonstrate the relationship of the electromotive force of a motor AC
thank you
Motional emf will be induced in the rotor. Use E=BLVsinθ*N (where v=rw and N=number of turns of rotor).
 
bassi ali said:
hi,
How can I demonstrate the relationship of the electromotive force of a motor AC
thank you
For detailed demo, you can first prove the motional emf equation using Lorentz's force(F=BILsinθ) applied on electrons of a conductor and then apply the emf equation to this alternator.
 
which force you talk about ?
the rectangle is fixed and the flow varies,
I think to use the flow of magnetic induction,
I think to use Faraday's relationship e = - dΦ / dt (the derivative currency flows on derivative temp).
in using Φ=∫∫ B.dS
 
bassi ali said:
the rectangle is fixed and the flow varies,
Then you should use Faraday's laws.
bassi ali said:
I think to use Faraday's relationship e = - dΦ / dt (the derivative currency flows on derivative temp).
in using Φ=∫∫ B.dS
Right.
 
but i find this expression : E = N L r w B cos(wt)
====> must find sin (wt) instead of cos (wt)
 
bassi ali said:
but i find this expression : E = N L r w B cos(wt)
====> must find sin (wt) instead of cos (wt)
Then you should assume the varying flux as a cosine wave.
sin(wt)=cos(π/2-wt).
 
i have cos(wt) not sin(wt) !
 
bassi ali said:
i have cos(wt) not sin(wt) !
Your varying flux function should be predefined, either sin or cos. If it is sin, emf will be in cos(wt).
 

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