Calculate the energy and wavelength of the photon

AI Thread Summary
To calculate the energy and wavelength of a photon emitted when an atom transitions from an excited state to the ground state, the energy of the photon is equal to the energy lost by the electron, which is 1.8 eV. This energy can be converted to joules using the conversion factor of 1 eV = 1.6 x 10^-19 J, resulting in an energy of 2.88 x 10^-19 J. The wavelength can then be calculated using the formula E = hf, where h is Planck's constant and c is the speed of light, leading to the equation λ = hc/E. It's essential to ensure all values are in the correct units before performing the calculations. The discussion emphasizes the importance of unit conversion and applying the correct formulas to find the desired photon properties.
shezill
this was a question in a prevoius year exam that I am really stuck on.

An atom has an energy level 1.8 eV above ground state. When excited, it returns to the ground state and emits a photon. Ccalculate the energy and wavelength of the photon.

help me please
thank you
 
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Doesn't seem very difficult...

Energy of photon = energy lost by electron as it goes down the energy level.

Also, E = hf = h*c/l

Plug in the numbers...

And don't forget that 1 eV = 1.6 * 10^-19 J
 
Last edited:
but what numbers do i plug in. Do i have to use a fomula on the 1.8eV first to get the numbers or just use that.
 
Originally posted by shezill
but what numbers do i plug in. Do i have to use a fomula on the 1.8eV first to get the numbers or just use that.

1 eV = 1.6x10^-19 Joules

Convert it to Jays.
 
thank you very much
 
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