Calculate the frequency, in hertz (level n = 10 to level n = 5)

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The discussion revolves around calculating the frequency of a photon emitted when an electron transitions from energy level n = 10 to n = 5 in a hydrogen atom. The user initially applied the Rydberg formula to find the wavelength and subsequently converted it to frequency, arriving at a value of 9.89e14 Hz. However, they expressed confusion over the accuracy of their result and whether the atomic number (Z) should be considered, as the Rydberg formula can vary for hydrogen-like atoms with different Z values. The user also acknowledged a possible mistake in posting the question in the wrong section of the forum.
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Calculate the frequency, in hertz, of the photon that is emitted when a electron falls from level n = 10 to level n = 5 in the H atom.

Enter a numeric answer only, no units.


I tried asking in other places but ppl are so ambiguous about it.
:( please help me.

I used rydberg formula:
1/λ = RH ∙ (1/n₁² - 1/n₂²)
(RH rydberg constant for hydrogen, n₁ lower level, n₂ higher level)

Hence:
λ = 1/ [ 1.09678×10⁷m⁻¹ ∙ (1/5² - 1/10²) ] = 3.0392×10⁻⁶m

and then I converted to Hz = 9.89e14 but i still GOT IT wrong :( Please help me someone!
 
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The above calculation is done for a hydrogen atom. Check the problem to see if a different Z is given. (the factor of Z^2is added to the rydberg equation for approximating photon frequencies of hydrogen-like atoms with a different atomic number.
 
elduderino said:
The above calculation is done for a hydrogen atom. Check the problem to see if a different Z is given. (the factor of Z^2is added to the rydberg equation for approximating photon frequencies of hydrogen-like atoms with a different atomic number.

I don't understand. So there's another Z? But I thought it is only 5 and 10?

oh dear. i think i posted in the wrong section.
(please move this thread) thanks!
 
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