# What mass of oxygen is liberated?

1. Dec 9, 2015

### science_rules

1. The problem statement, all variables and given/known data
This is a solved example problem in my chemistry book: What mass of oxygen gas O2 is liberated when a 2.5 gram sample of sodium nitrate NaNO3 is heated? Please keep in mind that I am self-studying, I am not currently in chemistry class.

2. Relevant equations
2NaNO3 ---> 2NaNO2 + O2
Known: 2.5 g NaNO3, 85 g of NaNO3/1 mole NaNO3, 1 mole O2/2 moles NaNO3, and 32 g O2/1mole O2
Unknown: mass O2 g
3. The attempt at a solution
This is how it was solved: 2.5 g NaNO3 X (1 mole 3/85 g NaNO3) X (1 mole O2/2 moles NaNO3) X (32 g O2/1 mole O2) = 0.47 g O2 What I don't understand is how they got the 85 grams of NaNO3 and the 32 grams of O2????? Can someone please show me step-by-step how they got the 85 grams and the 32 grams?? Are these related to the atomic mass of each element?

2. Dec 9, 2015

### epenguin

Yes they are. There is surely a table of atomic masses in your book. And these are roughly 23 for Na, 14 for N and 16 for O. 23 + 14 + 3×16 = 85. Likewise 2×13 = 32.

Why they do these calculations in this way is surely explained in your book.

We can't substitute for your book - I would only say that if you have difficulty then with the formulae then imagine the atoms as little blobs and draw them so the molecule has say a black blob for Na, a gray blob for N and three white blobs for the three O in NaNO3. Each blob has the weight or mass that we said. Then in a chemical reaction you picture them as moving about. Maybe this will make it clear for you at the start and later you will be able to do without it

The guy who invented the atomic theory represented atoms and molecules this way, but it is too cumbersome for printers.

3. Dec 9, 2015

### science_rules

okay, thankyou, I will look at my book.