Calculate the maximum height that m1 and m2 rise after collision?

AI Thread Summary
To calculate the maximum height that blocks m1 and m2 rise after their elastic collision, first determine the speed of m1 as it falls through the quarter circle from point A to B. This can be achieved by applying energy conservation principles, where the potential energy at point A is converted to kinetic energy at point B. After finding m1's velocity, use the conservation of momentum during the collision at point B to find the velocities of both blocks post-collision. Finally, apply energy conservation again to calculate the maximum height each block reaches after the collision. The solution involves understanding the dynamics of elastic collisions and energy transformations in a frictionless environment.
kalisious
Messages
13
Reaction score
0

Homework Statement


Consider a frictionless track. Imagine point A to B is one quarter of a circle; point B to C is a horizontal flat plane; point C to D is also one quarter of a circle.

The block m1 is released from A. It makes a head-on elastic collision at B with m2 (that is initially at rest) Calculate the maximum height to which m1 and m2 rise after collision.

m1 = 2kg
m2 = 10 kg
radius of quarter circles = 4.9 m


Homework Equations


p=mv

m1vf + m2vi = (m1 + m2)v

y=1/2 at^2


The Attempt at a Solution


I am not quite sure how to attempt a solution.
 
Physics news on Phys.org
Can you find out how fast m1 is going after it falls through the quarter of a circle A to B? Then you could do conservation of momentum on the collision at B.
 
I understand the equation for conservation of momentum, but how do I go about finding the velocity as you mentioned?
 
Draw the diagram. You should see how high above the BC horizontal section m1 is initially. From the initial height, you can calculate its speed after falling through the height either by using forces or energies.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top