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Calculate the specific heat capacity of this metal

  • #1
When a 35 gram piece of some metal at 100°C is placed in water, it loses 775 calories of heat while cooling to 30°C. Calculate the specific heat capacity of this metal.

Q = mc(DELTA)T

T = 70 degrees C
m = 35 g
Q = 775 cal ??


When i plugged it in i got 0.34 but the program said it was wrong.....and then i tried


c- 775 = (70)(35)c
c = 2.90

but I'm afraid to enter this answer because I only have one more chance to get it right...
 

Answers and Replies

  • #2
142
0
When a 35 gram piece of some metal at 100°C is placed in water, it loses 775 calories of heat while cooling to 30°C. Calculate the specific heat capacity of this metal.

Q = mc(DELTA)T

T = 70 degrees C
m = 35 g
Q = 775 cal ??


When i plugged it in i got 0.34 but the program said it was wrong.....and then i tried


c- 775 = (70)(35)c
c = 2.90

but I'm afraid to enter this answer because I only have one more chance to get it right...
When i plugged everything in i got c=.316 = 775/(35*70)
 
  • #3
Thank you so so so much!
 

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