# Calculate the specific heat capacity of this metal

When a 35 gram piece of some metal at 100°C is placed in water, it loses 775 calories of heat while cooling to 30°C. Calculate the specific heat capacity of this metal.

Q = mc(DELTA)T

T = 70 degrees C
m = 35 g
Q = 775 cal ??

When i plugged it in i got 0.34 but the program said it was wrong.....and then i tried

c- 775 = (70)(35)c
c = 2.90

but I'm afraid to enter this answer because I only have one more chance to get it right...

## Answers and Replies

When a 35 gram piece of some metal at 100°C is placed in water, it loses 775 calories of heat while cooling to 30°C. Calculate the specific heat capacity of this metal.

Q = mc(DELTA)T

T = 70 degrees C
m = 35 g
Q = 775 cal ??

When i plugged it in i got 0.34 but the program said it was wrong.....and then i tried

c- 775 = (70)(35)c
c = 2.90

but I'm afraid to enter this answer because I only have one more chance to get it right...

When i plugged everything in i got c=.316 = 775/(35*70)

Thank you so so so much!