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Calculate the specific heat capacity of this metal

  1. Apr 30, 2009 #1
    When a 35 gram piece of some metal at 100°C is placed in water, it loses 775 calories of heat while cooling to 30°C. Calculate the specific heat capacity of this metal.

    Q = mc(DELTA)T

    T = 70 degrees C
    m = 35 g
    Q = 775 cal ??


    When i plugged it in i got 0.34 but the program said it was wrong.....and then i tried


    c- 775 = (70)(35)c
    c = 2.90

    but I'm afraid to enter this answer because I only have one more chance to get it right...
     
  2. jcsd
  3. Apr 30, 2009 #2
    When i plugged everything in i got c=.316 = 775/(35*70)
     
  4. Apr 30, 2009 #3
    Thank you so so so much!
     
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