Calculate the surface temperature of a human body

AI Thread Summary
The discussion focuses on calculating heat transfer and temperature in various scenarios, including building insulation and human body radiation. For the insulation question, the user calculated a heat flow rate of 2.42 W using the correct resistance and heat transfer formulas. In the human body radiation calculation, the user found a surface temperature of 306.10 K and a net heat loss of 108.31 W, which aligns with the Stefan-Boltzmann Law. The root mean square speed of nitrogen molecules was calculated to be 510.89 m/s, with temperatures for half and double that speed determined to be 73.28 K and 1,172.60 K, respectively. Overall, the calculations appear to be correct, and the user is encouraged to verify their results with provided references.
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I am unsure about some of my formulae and answers I would be very grateful if someone could clarify these please

Q1 The insulating layer on the inner wall of a building is made from a
compound layer of laminated board (inner) and styrofoam (outer). The
thickness of the board is 0.02 m and of the styrofoam, 0.06 m. If the
temperature at the surfaces of the layer are 20C (inner) and 5C (outer),
calculate the rate of flow of heat per m 2 through the layer and the
temperature at the board-styrofoam interface. The thermal conductivities
are 0.1 Js -1 m -1 C -1 for the board and 0.01 J s -1 m -1 C -1 for the styrofoam.

used the formula R=L/k to find the resistance of both then subbed in formula P=A(T2-T1)/(R1+R2)
Answer 2.42W

Q2 Calculate the surface temperature of a human body of surface area 1.2
m 2 , which emits radiation at a rate of 597 W. Assume that the body
behaves as a perfect black body. If the temperature of the surroundings is
18° °° °C, calculate the net loss of heat by radiation by the body.

Used the formula Aε(5.6703x10^-8)T^4=Q/T=P

Answer T=306.10k
Orig temp T=291.16k
Aε(5.67...)(T2^4-T1^4)
Answer 108.31W

Q3 Calculate the root mean square speed of nitrogen
molecules at 20 C. At what temperatures will the RMS speed be a) half that
value and b) twice that value?
The molar mass of nitrogen is 28x10 -3 kg mol -1 .

Vrms=sq root 3RT/M
Answer 510.89
Answer 2 73.28k
Answer 3 1,172.60k

Please confirm if these are done correctly or if not please lead me in the right direction thanks!
 
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