Calculate Third Force Direction and Magnitude | Forces and Velocity Problem Help

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An object is subjected to three forces and moves with constant velocity, with one force of 6.5N in the positive x direction and another of 4.4N in the negative y direction. The magnitude of the third force is calculated to be 7.9N. The user struggles to find the correct direction, initially using the tangent function but obtaining an incorrect result of 0.59507 instead of the expected 34.1 degrees. The issue may stem from the calculator being set to radians instead of degrees. Properly adjusting the calculator settings should yield the correct direction for the third force.
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Problem-
An Object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a magnitude of 6.5N; a second force has a magnitude of 4.4N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.

answer-
(6.5^2 + 4.4^2)^1/2
=7.9N

Am having problems getting the answer for the direction. I used
Tan^- (4.4/6.5)= but I get .59507

and the answer in the back of the book is 34.1 for the direction. What am I doing wrong?please help
 
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Your calculator is in radians.:)
 
thanks for the help
 

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