Calculate Torque for Pin: L=100.9 cm, M=3.98 kg, m=537 g.

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To calculate the torque exerted by the pin to prevent the rod from rotating, the relevant equation is Torque = distance from the pivot * force. The problem involves a rod of length 100.9 cm with a mass of 3.98 kg and an additional mass of 537 g. The torque from the rod's mass is calculated by treating it as concentrated at its center, while the torque from the hanging mass is also considered. The total torque is found by summing the individual torques from both the rod and the hanging mass. This approach effectively addresses the problem of maintaining equilibrium at the pivot point.
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Torque of a pin. Please Help!

Homework Statement


How much torque must the pin exert to keep the rod from rotating? (L=100.9 cm, M=3.98 kg, m=537 g.)
I attached the picture of the problem. I am unsure how to approach the problem. I am looking through my College Physics and cannot find an equation to solve this problem. Help please!

Homework Equations


Torque=distance from the pivot*the force


The Attempt at a Solution

 

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PoPrOcKsRoCk said:

Homework Statement


How much torque must the pin exert to keep the rod from rotating? (L=100.9 cm, M=3.98 kg, m=537 g.)
I attached the picture of the problem. I am unsure how to approach the problem. I am looking through my College Physics and cannot find an equation to solve this problem. Help please!

Homework Equations


Torque=distance from the pivot*the force
Okay, so based on that equation how much torque do the bar and hanging mass each exert on the pivot point (pin location)?

You may treat the bar's mass as being located at the bar's center.
 


I got it.

I used the equation T=Fr for the Torque of rod M and the Torque of the weight of m then added both torques.

Thank you.
 

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