Calculate total destruction OF NUCLEAR BOMB

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To calculate the volume of total destruction from a nuclear bomb, a complex formula is needed, as existing resources often provide only basic information. The Tsar Bomba, with a yield of 50 MT TNT, has a destruction radius of approximately 35 km, suggesting that a significantly higher yield would be required to achieve a total destruction radius of 150 km. Discussions indicate that while smart weapons are more precise, the focus remains on understanding the destructive potential of nuclear weapons. Resources like Wikipedia and specialized apps can assist in approximating these calculations. Ultimately, the practicality of determining yields for larger bombs is questioned, given advancements in conventional weaponry.
maghilani
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i need to calculate the volume of total destruction of a nuclear bomb

its like here
http://en.wikipedia.org/wiki/File:Tsar_Bomba_Paris.png

what formula i need to use to calculate area of total destruction
zar bomb already has some infos : 50MT tnt = 35km total destruction (detonation height 4km nn)

formula must be complicated enough that i didnt found it on google, and i know that nuclear services of those countries that have nuclear weapons have experts which calculate its power precisely and i need only approximating formula

how much MT TNT does a bomb need (with usual construction circumstances(usual material which is used for nuclear bomb, like zar bomb/trinity)) to reach a total destruction of 150km in diameter?

if i calculate it my way then it wouldn't be correct

how much TNT for 150km of TOTAL DESTRUCTION


(i give u software for not commenting on my writing style)
 
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maghilani said:
i need to calculate the volume of total destruction of a nuclear bomb
Better to use smart weapon with non nuclear warhead might to kill only bad guys.
Joke.
 
Here is a description of the Tzar Bomba test
http://en.wikipedia.org/wiki/Tsar_Bomba#The_test

One comment indicates a destructive radius of ~34 mi (~54 km), or a diameter of 68 mi (~108 km). The bomb yield was apparently reduced to reduce fallout. So apparently, if it had been constructed as orginially designed, it's destructive range would have increased.

What is the point of determining a yield of a larger bomb? It seems rather impractical.
 
clancy688 said:
You know, smart bombs are very, very smart and accurate... they always hit the ground.
That's right, but the matter is the target located on that hitting point or no
I never heard for last years that Western allies’ countries (NATO, etc.) are developing now new nukes. I think this is because existing nuke weapons answer their demands.
But at the same time they actively develop very accurate weapons with conventional warheads.
 
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