Calculate Volume of Diving Bell Air Space at 50m Depth

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To calculate the volume of the air space in a diving bell at a depth of 50 meters, the ideal gas law can be applied. The initial pressure at the surface (P1) is 1 atm, while the pressure at 50 m depth (P2) can be determined using the formula P2 = P1 + ρgΔz, where ρ is the density of seawater (1.025 g/cm³), g is gravitational acceleration, and Δz is the depth change. The volume of the air space will decrease as pressure increases with depth, following the relationship V1P1 = V2P2. The problem requires calculating the new volume (V2) based on these pressure changes. Understanding the relationship between pressure and volume is crucial for solving this diving bell scenario.
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Homework Statement


A diving bell has an air space of 3.0 m2 when on the deck of a boat. What is the volume of the air space when the bell has been lowered to a depth of 50 m? Take the mean density of sea water to be 1.025 g cm-3 and assume that the temperature is the same as on the surface.


Homework Equations



PV = nRT

The Attempt at a Solution



I'm thinking I should use the ideal gas law to solve this problem.

V1P1 = nRT

V2P2 = nRT

V1P1 = V2P2

P1 = 1 atm (at surface of water)

P2 = ? (would I use the density of sea water and surface area of diving bell somehow?)

Thanks!
 
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P_{2}=P_{1}+\rho g \Delta z
where
g=gravitational acceleration
\Delta z= difference in depth
 
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