Calculate wavelength to frequency

AI Thread Summary
The discussion focuses on calculating the frequency corresponding to a wavelength of 600nm using the formula f = c/l. The correct calculation yields a frequency of 500 THz, not 5 pHz as initially stated. A user points out that MATLAB's output of 5.0075e+004 indicates a misunderstanding in input formatting, leading to incorrect results. Clarifications on MATLAB's scientific notation and proper input syntax are provided. The final consensus confirms that the correct frequency for 600nm is indeed 500 THz.
dervast
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Hi i am trying to calculate what is the frequency of the 600nm that our eye can see...
I am calculating the
f=(c/l)
(3*10^8)/(600*10^-9)=0.5*10^19 whics means 5phZ... Is it coreect?

I have tried to calculate using MATLAB but the results don't agree
>> (3*10^8)/(600*10-9)

ans =

5.0075e+004
 
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I think you meant 0.5Phz or 500Thz, which is correct.
 
thx a lot

(3*10^8)/(600*10-9)
(3*10^8)/(6*10-7)=0.5*10^15=500Thz and u are right

How can u understand the matlabs ouput?
5.0075e+004
 
e+004 means E04 which is basically 5.0075 * 10^4

I think you screwed up when you entered: (3*10^8)/(600*10-9)

The program probably did 600 * 10 * -9 or something because you didn't enter it in correctly.
 
>> (3*10^8)/(600*10^-9)

ans =

5.0000e+014

thx
 
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