Calculate Weight Component on Inclined Plane

AI Thread Summary
To calculate the weight component acting parallel to an inclined plane at 30 degrees, the formula W*sin(θ) is used, where W represents the weight of the box. Given that sin(30) equals 0.5, the parallel component of the weight simplifies to 0.5W. The discussion highlights the confusion around the necessary formulas, but ultimately confirms that the answer is 0.5W. Understanding that W equals M*g is crucial for solving similar problems. This approach effectively clarifies the calculation process for inclined planes.
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Homework Statement


the weight of a box on a plane inclined at 30 def is represented by the vector W. What is the magnitude of the component of the weight that acts parallel to the incline.
Answer is given in terms of W
possible anwsers .5W 1.5W .87W and W


Homework Equations





The Attempt at a Solution


M x g x sin(30)= 4.9
??
not sure what formula is needed to be used here
 
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W = mg. So
W*sinθ = ?
 
You don't know M, but you do know that W = M*g
so you have W*sin(30) = 0.5*W
 
wow i made it so much harder than what it needed to be thanks
 
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