1. A 40kg stone is pulled slowly up a smooth ramp inclined at 30o to the horizontal. It stops at the top, at a height of 100m above its initial height. Calculate the work done by: a) Using 'work done = force x distance moved in direction of force'. b) Using conservation of energy 2. F=ma F-Fgravity=mgsin(theta) Work done=Fscos(theta) 3. Weight = 400N F-400=400sin(30)=600N Work done = 600 x 100cos(30) = 52kJ (2sf) Not sure this is correct please advise?