- #1
lemon
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1. A 40kg stone is pulled slowly up a smooth ramp inclined at 30o to the horizontal. It stops at the top, at a height of 100m above its initial height. Calculate the work done by:
a) Using 'work done = force x distance moved in direction of force'.
b) Using conservation of energy
2. F=ma
F-Fgravity=mgsin(theta)
Work done=Fscos(theta)
3. Weight = 400N
F-400=400sin(30)=600N
Work done = 600 x 100cos(30) = 52kJ (2sf)
Not sure this is correct
please advise?
a) Using 'work done = force x distance moved in direction of force'.
b) Using conservation of energy
2. F=ma
F-Fgravity=mgsin(theta)
Work done=Fscos(theta)
3. Weight = 400N
F-400=400sin(30)=600N
Work done = 600 x 100cos(30) = 52kJ (2sf)
Not sure this is correct
please advise?