Calculating 2D Momentum Collision with Unknown Speeds and Angles

AI Thread Summary
The discussion focuses on calculating 2D momentum collision involving unknown speeds and angles. The equations presented are derived from the momentum conservation principle, using trigonometric components for two colliding objects. There is uncertainty regarding the correctness of the attempted solution and the signs in the equations. Participants seek clarification on the direction of the cue ball post-impact and how to isolate the variable V. The final angles for the objects after the collision are specified as +60° for the red ball and -20° for the white ball.
Theudius
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lAsytPR.png

Homework Equations


[/B]
P = mv

The Attempt at a Solution


[/B]
VCos(30) + 0 = nCos(60) + 2Cos(20)
VSin(30) + 0 = nSin(60) + 2Sin(20)

where I let n = any speed,
I'm not sure if my attempt at the solution is correct.
 
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Theudius said:
1. View attachment 211369

Homework Equations


[/B]
P = mv

The Attempt at a Solution


[/B]
VCos(30) + 0 = nCos(60) + 2Cos(20)
VSin(30) + 0 = nSin(60) + 2Sin(20)
Check signs in 2nd equation.
 
I don't see anything wrong with the signs in the second equation could you explain further also how would I obtain V?
 
Theudius said:
I don't see anything wrong with the signs in the second equation could you explain further
What direction does the cue ball go after impact?
also how would I obtain V?
2 equations, 2 unknowns.[/QUOTE]
 
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Theudius said:
I don't see anything wrong with the signs in the second equation could you explain further also how would I obtain V?

The final angles are ##+60^o## for red and ##-20^o## for white.
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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