Calculating 2D Momentum Collision with Unknown Speeds and Angles

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Homework Help Overview

The discussion revolves around a 2D momentum collision problem involving unknown speeds and angles. Participants are examining the equations related to momentum conservation in a collision scenario, specifically focusing on the velocities and directions of the objects involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to set up equations based on the conservation of momentum, questioning the correctness of their signs and the overall approach. There is a focus on how to isolate variables, particularly the unknown speed V, and the implications of the angles post-collision.

Discussion Status

There is an ongoing examination of the equations presented, with participants seeking clarification on specific aspects, such as the signs in the equations and the direction of the cue ball after impact. Multiple interpretations of the equations and their implications are being explored, but no consensus has been reached.

Contextual Notes

Participants are working under the constraints of the problem setup, which includes unknown variables and the need to derive relationships from the equations provided. There is an emphasis on ensuring the equations reflect the physical scenario accurately.

Theudius
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1.
lAsytPR.png

Homework Equations


[/B]
P = mv

The Attempt at a Solution


[/B]
VCos(30) + 0 = nCos(60) + 2Cos(20)
VSin(30) + 0 = nSin(60) + 2Sin(20)

where I let n = any speed,
I'm not sure if my attempt at the solution is correct.
 
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Theudius said:
1. View attachment 211369

Homework Equations


[/B]
P = mv

The Attempt at a Solution


[/B]
VCos(30) + 0 = nCos(60) + 2Cos(20)
VSin(30) + 0 = nSin(60) + 2Sin(20)
Check signs in 2nd equation.
 
I don't see anything wrong with the signs in the second equation could you explain further also how would I obtain V?
 
Theudius said:
I don't see anything wrong with the signs in the second equation could you explain further
What direction does the cue ball go after impact?
also how would I obtain V?
2 equations, 2 unknowns.[/QUOTE]
 
Last edited:
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Theudius said:
I don't see anything wrong with the signs in the second equation could you explain further also how would I obtain V?

The final angles are ##+60^o## for red and ##-20^o## for white.
 
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