- #1
muppet
- 602
- 1
The first part to an exam question I had to sit at the end of last year. It defeated me then, and I still can't do it now, which worries me more than a little!
A solid cylinder of radius 10 cm and mass 12 kg starts from rest and rolls
without slipping a distance L = 6:0 m down a roof that is inclined at an
angle \theta = 30\circ
Show that the acceleration of the cylinder is given by
a= \frac{2gsin\theta}{3}
The acceleration of a block down a frictionless incline is just gsin \theta
The moment of inertia of a solid cylinder of mass m and radius r
is given by I = \frac{1}{2}mr^{2}
As 2, but I really don't know where the factor of two thirds comes from. The question was worth 6 marks.
Homework Statement
A solid cylinder of radius 10 cm and mass 12 kg starts from rest and rolls
without slipping a distance L = 6:0 m down a roof that is inclined at an
angle \theta = 30\circ
Show that the acceleration of the cylinder is given by
a= \frac{2gsin\theta}{3}
Homework Equations
The acceleration of a block down a frictionless incline is just gsin \theta
The moment of inertia of a solid cylinder of mass m and radius r
is given by I = \frac{1}{2}mr^{2}
The Attempt at a Solution
As 2, but I really don't know where the factor of two thirds comes from. The question was worth 6 marks.
