Calculating Amplitude in Simple Harmonic Motion

[affirmative]

My question is with part c, more specifically the calculating of the amplitude part.
[PLAIN]http://img691.imageshack.us/img691/1750/shmquestion.jpg

The answer to the question is:
[PLAIN]http://img80.imageshack.us/img80/8921/shmanswer.jpg

I do not understand how to arrive at this conclusion in order to calculate the amplitude; it baffles me. Any poking or prodding in the right direction (or even an outright answer) would be greatly appreciated.

 

[Je m'appelle]

Isn't the amplitude

$$A = \sqrt{c^2_1 + c^2_2}$$

Where

$$x(t) = c_1cos(wt) + c_2sin(wt)$$

 

[affirmative]

I have no idea unfortunately. My question is how did the examiner arrive at the answer above (it is the verbatim answer for the past paper I'm currently working on).

 

[annumarch]

see the equilibrium point of smaller block is .05g/k = .01 m but initially it is at .03 m thus this excess distance is its amplitude . as after each oscillation it wll come back to this point .

 

[affirmative]

Thank you very much, that actually kind of makes sense now!