Calculating Angular Velocity at the End of a Time Interval

AI Thread Summary
To calculate the angular velocity at the end of a 2.0-second interval for a wheel with a constant angular acceleration of 2.0 rad/s², the kinematic equation θf = θi + ωi*t + 0.5*α*t² is applied. The wheel completes 2.165 revolutions, which converts to approximately 13.6 radians. Using the known values, the initial angular velocity (ωi) is assumed to be zero, leading to the calculation of final angular velocity (ωf). The calculated values are significantly higher than the provided answer options, indicating a potential error in the initial assumptions or calculations. The discussion emphasizes the need for clarity in the application of kinematic equations to solve for angular velocity accurately.
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Homework Statement


A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 turns through 2.165 revolutions during a 2.0 s time interval. What is the angular velocity at the end of this time interval?


Homework Equations


I was using the kinematic Equations
\thetaf = \thetai + \omegait + 0.5\alphat2

Am i doing something wrong?
The answers that I can choose are, 9.7 rad/s, 9.1 rad/s, 9.3 rad/s, 9.5 rad/s, 8.8 rad/s

All the answers I get are way larger

I must be doing something obviously wrong but I just can't see it.
 
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Lets see your work then.
 
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